3(x+3)=2[x-(3-x)]

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Solution for 3(x+3)=2[x-(3-x)] equation:


Simplifying
3(x + 3) = 2[x + -1(3 + -1x)]

Reorder the terms:
3(3 + x) = 2[x + -1(3 + -1x)]
(3 * 3 + x * 3) = 2[x + -1(3 + -1x)]
(9 + 3x) = 2[x + -1(3 + -1x)]
9 + 3x = 2[x + (3 * -1 + -1x * -1)]
9 + 3x = 2[x + (-3 + 1x)]

Reorder the terms:
9 + 3x = 2[-3 + x + 1x]

Combine like terms: x + 1x = 2x
9 + 3x = 2[-3 + 2x]
9 + 3x = [-3 * 2 + 2x * 2]
9 + 3x = [-6 + 4x]

Solving
9 + 3x = -6 + 4x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4x' to each side of the equation.
9 + 3x + -4x = -6 + 4x + -4x

Combine like terms: 3x + -4x = -1x
9 + -1x = -6 + 4x + -4x

Combine like terms: 4x + -4x = 0
9 + -1x = -6 + 0
9 + -1x = -6

Add '-9' to each side of the equation.
9 + -9 + -1x = -6 + -9

Combine like terms: 9 + -9 = 0
0 + -1x = -6 + -9
-1x = -6 + -9

Combine like terms: -6 + -9 = -15
-1x = -15

Divide each side by '-1'.
x = 15

Simplifying
x = 15

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